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O toks skaiciavimas kaip postu auksciau - tai da nu nx... :D :D :D

Linas Petkevicius <linas@NENENEinfonova.lt> wrote in
news:guu5at$dv8$1@trimpas.omnitel.net: 

> Man atrodo pigiau bus i klausima "Kiek turiu saliarkos ?", gauti
> atsakyma - "puse metro".
> 
> "MinVodai" <minvodai@gmail.com> wrote in message 
> news:guu4nu$ct5$1@trimpas.omnitel.net...
>> ir mano nuoroda su integralais, del bachkos isgaubimu..
>> http://www.sjsu.edu/faculty/watkins/ndim.htm
>>
>> "Linas Petkevicius" <linas@NENENEinfonova.lt> wrote in message 
>> news:gutkrg$gcr$1@trimpas.omnitel.net...
>>>I pagalba Kulibkinui:
>>>
>>> http://www.lmnoeng.com/Volume/InclinedCyl.htm
>>>
>>> "Eex" <eex_trint_@dtiltas.lt> wrote in message 
>>> news:guthpj$bna$1@trimpas.omnitel.net...
>>>> i vakara namie pabandysiu, bet negarantuoju, kad iseis. idomios
>>>> uzduotys tokios man :)
>>>>
>>>> "MinVodai" <minvodai@gmail.com> wrote in message 
>>>> news:gutck8$587$1@trimpas.omnitel.net...
>>>>> gal turi varianta, jei bachka su isgaubimu?
>>>>> sakykim tokios formos:
>>>>> http://www.jaklic.com/images5/cisterna-ovalna1.gif
>>>>>
>>>>>
>>>>> "eex" <eex_trint_@dtiltas.lt> wrote in message 
>>>>> news:gus2g2$28h$1@trimpas.omnitel.net...
>>>>>> va ekscelinis variantas :)
>>>>>>
>>>>>> "ramunas" <doobas@gmail.com> wrote in message 
>>>>>> news:gurpj3$mii$1@trimpas.omnitel.net...
>>>>>>> yo :) bet aisku visa problema issprende autocadas :)
>>>>>>>
>>>>>>> "Eex" <eex_trint_@dtiltas.lt> wrote in message
>>>>>>> news:gurle7$efu$1@trimpas.omnitel.net...
>>>>>>>> ta prasme negali nuopjovos ploto rasti?
>>>>>>>>
>>>>>>>> "ramunas" <doobas@gmail.com> wrote in message
>>>>>>>> news:gurghc$5ac$1@trimpas.omnitel.net...
>>>>>>>>> na manau cia belekas turi gali paskaiciuoti. taciau ta
>>>>>>>>> nuopjovos plota
>>>>>>>>> .... googlas kaip sakiau nepadeda ... pilna visokiu neaiskiu 
>>>>>>>>> sapaliojimu
>>>>>>>>> ...
>>>>>>>>>
>>>>>>>>> "Donatuksss" <donatuxxx@takas.lt> wrote in message
>>>>>>>>> news:gur9pb$nvh$1@trimpas.omnitel.net...
>>>>>>>>>> jei backa - paverstas ritinys, tai ritinio turis yra lygus jo
>>>>>>>>>> pagrindo
>>>>>>>>>> (skritulio) plota padauginus is aukscio (ilgio -  kai
>>>>>>>>>> paverstas) Nepilnos backos turis  - skritulio nuopjovos ploto
>>>>>>>>>> ir ilgio sandauga
>>>>>>>>>>
>>>>>>>>>> Dede Goooooooglas apie skritulio nuopjovos plota zino daugiau
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> "ramunas" <doobas@gmail.com> wrote in message
>>>>>>>>>> news:gur210$8q6$1@trimpas.omnitel.net...
>>>>>>>>>>> yra cia tokia tatai dydele backa. buvusi kuro talpykla.
>>>>>>>>>>> reikia pasidaryti graduote, kad pamatavus kiek yra gylio
>>>>>>>>>>> paskaiciuoti turi
>>>>>>>>>>> esancio skyscio.
>>>>>>>>>>> reiktu pasidaryti graduote kas 5cm tarkim. kaip pagal
>>>>>>>>>>> radiusa kas tuos
>>>>>>>>>>> 5cm apskaiciuoti stygos ilgi ir su ja atskiriamo plotelio
>>>>>>>>>>> plota? cia tokia formule radau senoj knygoj. r=h/2 + s^2/8h
>>>>>>>>>>> is jos kaip ir
>>>>>>>>>>> issitraukiu r. bet biski be rysio gaunasi :/ gal kas kokiu 
>>>>>>>>>>> formulyciu
>>>>>>>>>>> pasakytumet? googlas nieko kotais nesako :(
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>
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>>>>>>>
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>>>>>
>>>>>
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