Re: kiek puciat oro? [zhegonskas @ 2009-04-29 15:50:17]

Tema: Re: kiek puciat oro?
Autorius: zhegonskas
Data: 2009-04-29 15:50:17
o ko nekyla? nieks gi ten nesprogsta nuo 2,8 :) tik kad kietos bus

as vokietijoje vazineju su rekomenduojamais prie 160-210 greiciu 2.8 
prieki, 3.0 gale, kazkaip ir mieste neparina toks kietumas, o vat i 
lietuva grizes ishleidziu iki 2.4/2.6 nes kitaip dantis palikt galima, 
ypac kaune, kur tiesiog NERA lygaus asfalto :)

On 2009-04-29 09:49:59 +0200, "TomS" <ner@ner.ner> said:

> 
> 
> pas mane ir panasiai prie "polnaja nagruzka" siulo.. bet ranka nekyla =
> kazkaip 2.8 pust :)
>   "Rimvydas" <rmsas@everyday.com> wrote in message =
> news:gt8v9m$c0r$1@trimpas.omnitel.net...
>   Jei auto pakrautas keleiviais ar bulv=C4=97m, bent jau gal=C4=85 =
> reikia gerokai pap=C5=ABsti, pagal manual=C4=85 FFII iki 2.8 (=C5=BEr. =
> foto)
> 
>     "mumum=C4=8Dik zergatronas" <zz@mumumba.zerg> wrote in message =
> news:gt8u90$a29$2@trimpas.omnitel.net...
>     trumpa apklausele :)
>     auto (jei kas zino ir svori kg), padangos, kiek puciat i prieki, =
> kiek i=20
>     gala..
> 
>     o tai man patarimai nuo 1.9 iki 2.4 svyruoja saltoms 195 50 R15 =
> padugnems
> 
> =EF=BB=BF<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
> <HTML><HEAD>
> <META content=3D"text/html; charset=3Dutf-8" http-equiv=3DContent-Type>
> <META name=3DGENERATOR content=3D"MSHTML 8.00.6001.18702">
> <STYLE></STYLE>
> </HEAD>
> <BODY bgColor=3D#ffffff>
> <DIV><FONT size=3D2 face=3DArial>pas mane ir panasiai prie "polnaja =
> nagruzka"=20
> siulo.. bet ranka nekyla kazkaip 2.8 pust :)</FONT></DIV>
> <BLOCKQUOTE=20
> style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; =
> PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px"=20
> dir=3Dltr>
>   <DIV>"Rimvydas" &lt;<A=20
>   href=3D"mailto:rmsas@everyday.com">rmsas@everyday.com</A>&gt; wrote in =
> message=20
>   <A=20
>   =
> href=3D"news:gt8v9m$c0r$1@trimpas.omnitel.net">news:gt8v9m$c0r$1@trimpas.=
> omnitel.net</A>...</DIV>
>   <DIV><FONT size=3D2 face=3DArial>Jei auto pakrautas keleiviais ar =
> bulv=C4=97m, bent jau=20
>   gal=C4=85 reikia gerokai pap=C5=ABsti, pagal manual=C4=85&nbsp;FFII =
> iki 2.8 (=C5=BEr.=20
>   foto)</FONT></DIV>
>   <DIV><FONT size=3D2 face=3DArial></FONT>&nbsp;</DIV>
>   <BLOCKQUOTE=20
>   style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; =
> PADDING-RIGHT: 0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
>     <DIV>"mumum=C4=8Dik zergatronas" &lt;<A=20
>     href=3D"mailto:zz@mumumba.zerg">zz@mumumba.zerg</A>&gt; wrote in =
> message <A=20
>     =
> href=3D"news:gt8u90$a29$2@trimpas.omnitel.net">news:gt8u90$a29$2@trimpas.=
> omnitel.net</A>...</DIV>trumpa=20
>     apklausele :)<BR>auto (jei kas zino ir svori kg), padangos, kiek =
> puciat i=20
>     prieki, kiek i <BR>gala..<BR><BR>o tai man patarimai nuo 1.9 iki 2.4 =
> 
>     svyruoja saltoms 195 50 R15 =
> padugnems</BLOCKQUOTE></BLOCKQUOTE></BODY></HTML>